Maths

Author Manisha Gupta asked on 2019-07-22 13:26:00

 

A =tan30 =1/√3

B= (tan60-tan30)/(1+tan60*tan30)  =√3-(1/√3)  /(1+ √3*1/√3)  =√3-(1/√3)/(1+1) =3-1/√3 /2 =2/√3*2 =1/√3

A=B