Probability

Author Atul asked on 2019-07-22 13:26:00

Solution plz

Let a1,a2,a3,a4,a5,a6 are the six faces

Probability of odd= 90% Probability of even

 a1+a3+a5=.9( a2+a4+a6)--------i

as Probability will not be greater than 1

therefore  a1+a2+a3+a4+a5+a6=1 ---------------------ii

 probability of every even is equal (given)

a2=a4=a6 

put the value in equation i

a1+a3+a5=.9( 3a2)

a1+a3+a5=2.7(a2)----------------iii

put the value of  equation (iii) in  equation (ii)

then 2.7a2+3a2=1

5.7a2=1

a2=1/5.7=.1754338

Now If the probability that the face is even given that it is greater than 3 is 0.75

a4+a6/(a4+a5+a6) =.75

2a2/ (a4+a5+a6)=.75  (  as a2=a4=a6  )

2a2/ .75= a4+a5+a6

2*(.1754338)/.75= a4+a5+a6

.467823= a4+a5+a6 (answer)